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Allegiant Air G4978 Flight Status from Akron to Saint Petersburg, United States today
Domestic flight Allegiant Air G4978 from Akron (CAK) United States to Saint Petersburg (PIE) United States operated by Allegiant Air. Scheduled time of departure from Akron-Canton Airport is 09:41 26 April 2024 America/New_York and scheduled time of arrival in St. Petersburg-Clearwater International Airport is 12:12 26 April 2024 America/New_York. The duration of the flight is 2 hours 31 minutes.
- Type: Domestic Flight
- Flight Duration: 2 hours 31 minutes
- Flight Distance: 1447 kms / 899 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Thursday, Friday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KTPA2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Akron: Friday 2024-04-26 03:30 AM
- Current Time in Saint Petersburg: Friday 2024-04-26 03:30 AM
Allegiant Air G4978 flight status on other days
Similar flight route from Akron (CAK) to Saint Petersburg (PIE)
Airline | Flight no | Departure | Arrival |
---|---|---|---|
G43591 Allegiant Air |
26/04/2024 09:06 (-5:00) |
2 hours 24 minutes 11:31 (-5:00) |
Frequently asked questions, answered
How long is the flight from Akron to Saint Petersburg?
On average, nonstop flight takes 2 hour(s) 31 minutes, with the flight distance of 1447 km (899 miles).
What type of aircraft is used for the Allegiant Air G4978 flight?
All Allegiant Air G4978 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G4978 flights are operated a week?
4 flights per week. The Flight Allegiant Air G4978 is operated on Monday, Thursday, Friday, Sunday.